What is the tension in each arm if the bar is gripped with both arms raised vertically overhead?
Q. A 59.8-kg high-school student hangs from an overhead bar with both hands. What is the tension in each arm if the bar is gripped with both arms raised vertically overhead? What is the tension in each arm when the arms make an angle of 39.00 o with respect to the vertical?
Asked by brandon - Fri Feb 19 22:25:25 2010 - - 1 Answers - 0 Comments
A. A 59.8-kg high-school student hangs from an overhead bar with both hands. What is the tension in each arm if the bar is gripped with both arms raised vertically overhead? 59.8 x 9.8 = 586.04 N 586.04/2 = 293.02 (each arm) What is the tension in each arm when the arms make an angle of 39.00 o with respect to the vertical? 293.02/sin(51) = 377.046 N
Answered by Physicsquest - Sat Feb 20 08:34:49 2010
Q. A 59.8-kg high-school student hangs from an overhead bar with both hands. What is the tension in each arm if the bar is gripped with both arms raised vertically overhead? What is the tension in each arm when the arms make an angle of 39.00 o with respect to the vertical?
Asked by brandon - Fri Feb 19 22:25:25 2010 - - 1 Answers - 0 Comments
A. A 59.8-kg high-school student hangs from an overhead bar with both hands. What is the tension in each arm if the bar is gripped with both arms raised vertically overhead? 59.8 x 9.8 = 586.04 N 586.04/2 = 293.02 (each arm) What is the tension in each arm when the arms make an angle of 39.00 o with respect to the vertical? 293.02/sin(51) = 377.046 N
Answered by Physicsquest - Sat Feb 20 08:34:49 2010
How does the surface tension of water compare with the surface tensions of most other liquids?
Q. Does the surface tension become higher, lower, or is about the same?
Asked by Valeria S - Tue Mar 24 23:32:55 2009 - - 1 Answers - 0 Comments
A. Water is generally considered to have a high surface tension compared to most other liquids. Although,the surface tension of water is nowhere near as high as that of mercury. Hope this helps.
Answered by Pat. Pending - Thu Mar 26 09:24:01 2009
Q. Does the surface tension become higher, lower, or is about the same?
Asked by Valeria S - Tue Mar 24 23:32:55 2009 - - 1 Answers - 0 Comments
A. Water is generally considered to have a high surface tension compared to most other liquids. Although,the surface tension of water is nowhere near as high as that of mercury. Hope this helps.
Answered by Pat. Pending - Thu Mar 26 09:24:01 2009
What is the tension in the string supporting the mass?
Q. A 5.0-kg mass is suspended by a string from the ceiling of an elevator that is moving upward with a speed which is decreasing at a constant rate of 2.0 m/s in each second. What is the tension in the string supporting the mass?
Asked by webs2slow4me - Wed Feb 4 09:53:03 2009 - - 1 Answers - 0 Comments
A. Two forces act on the object: T, the tension force acts up mg, the object's weight, acts down Let [up] be positive and [down] negative. Fnet = ma T - mg = ma T = m(a+g) T = 5.0(- 2.0 + 9.8) T = 39 N
Answered by unknown - Wed Feb 4 10:36:24 2009
Q. A 5.0-kg mass is suspended by a string from the ceiling of an elevator that is moving upward with a speed which is decreasing at a constant rate of 2.0 m/s in each second. What is the tension in the string supporting the mass?
Asked by webs2slow4me - Wed Feb 4 09:53:03 2009 - - 1 Answers - 0 Comments
A. Two forces act on the object: T, the tension force acts up mg, the object's weight, acts down Let [up] be positive and [down] negative. Fnet = ma T - mg = ma T = m(a+g) T = 5.0(- 2.0 + 9.8) T = 39 N
Answered by unknown - Wed Feb 4 10:36:24 2009
What is the tension in each string holding a 100N block at 45 degrees?
Q. There are two strings holding a suspended block that weighs 100N; both are at a 45 degree angle to the block. What is the tension in each of the strings? Is it 70.9N? I used 2Tsin(theta)=100N with theta=45 and solved for T.
Asked by tzier187 - Sun Oct 7 20:23:52 2007 - - 1 Answers - 0 Comments
A. You are correct, sir!
Answered by unknown - Sun Oct 7 20:36:04 2007
Q. There are two strings holding a suspended block that weighs 100N; both are at a 45 degree angle to the block. What is the tension in each of the strings? Is it 70.9N? I used 2Tsin(theta)=100N with theta=45 and solved for T.
Asked by tzier187 - Sun Oct 7 20:23:52 2007 - - 1 Answers - 0 Comments
A. You are correct, sir!
Answered by unknown - Sun Oct 7 20:36:04 2007
How does the tension in the string vary throughout the motion of a pendulum?
Q. Please help me, I'm stuck on this homework question about pendulums and simple harmonic motion: "How does the tension in the string vary throughout the motion? Be specific - what are the maximum and minimum values of force in the string?"
Asked by bohemianbum - Mon Dec 22 19:46:39 2008 - - 3 Answers - 0 Comments
A. The maximum value is when it is at the lowest point. The minimum value is where the speed is 0. These values are not fixed, it depends on the mass and the motion angle.
Answered by shihhua123 - Mon Dec 22 20:17:41 2008
Q. Please help me, I'm stuck on this homework question about pendulums and simple harmonic motion: "How does the tension in the string vary throughout the motion? Be specific - what are the maximum and minimum values of force in the string?"
Asked by bohemianbum - Mon Dec 22 19:46:39 2008 - - 3 Answers - 0 Comments
A. The maximum value is when it is at the lowest point. The minimum value is where the speed is 0. These values are not fixed, it depends on the mass and the motion angle.
Answered by shihhua123 - Mon Dec 22 20:17:41 2008
How do I know where the tension and guide pulley goes on my Shimano gears?
Q. I have taken my bike apart to clean and have noticed that one of the pulleys in the gear system is called 'Guide' the other 'Tension'. The tension pulley has a stronger bearing in the middle so I am guessing its not interchangleable with the guide pulley. Im just not sure where they go. Although I have a good idea. Can you help?
Asked by Dave G - Thu Mar 5 09:04:08 2009 - - 1 Answers - 0 Comments
A. The guide pulley is the upper pulley that guides the chain from one sprocket to the next, the tension pulley is the lower pulley that maintains spring tension on the chain. The upper pulley's bearing allows a bit of side to side movement of the chain to allow it to self center itself on the cassette sprockets.
Answered by mtrlbiker - Thu Mar 5 09:29:56 2009
Q. I have taken my bike apart to clean and have noticed that one of the pulleys in the gear system is called 'Guide' the other 'Tension'. The tension pulley has a stronger bearing in the middle so I am guessing its not interchangleable with the guide pulley. Im just not sure where they go. Although I have a good idea. Can you help?
Asked by Dave G - Thu Mar 5 09:04:08 2009 - - 1 Answers - 0 Comments
A. The guide pulley is the upper pulley that guides the chain from one sprocket to the next, the tension pulley is the lower pulley that maintains spring tension on the chain. The upper pulley's bearing allows a bit of side to side movement of the chain to allow it to self center itself on the cassette sprockets.
Answered by mtrlbiker - Thu Mar 5 09:29:56 2009
How do i avoid tension when cutting hair?
Q. I am a perfectionist in school for cosmetology but i notice i have so much tension my ends are not straight they always seem wavy. How do i avoid this but still have a nice straight edge?
Asked by queen b - Wed Mar 7 01:03:39 2007 - - 3 Answers - 0 Comments
A. Sectioning is important. If you don't section the hair off in small areas when cutting, you won't get an even line. When I was in my first cosmetology school, I was taught to section the hair in six areas - from ear to ear across the top of the head, then down the middle from the forehead to the nape of the neck, then splitting the back portion in half around the occipital bone. Right? When I transferred to a much better school I learned that it was better to do small sections. Section the front into three (not two) sections - one section on top of the head from forehead to crown, about the width where the skull begins to curve down towards the ear. Then comb a section from the tip of the ear towards the front. Then section the back… [cont.]
Answered by wickdsinnr - Wed Mar 7 01:30:09 2007
Q. I am a perfectionist in school for cosmetology but i notice i have so much tension my ends are not straight they always seem wavy. How do i avoid this but still have a nice straight edge?
Asked by queen b - Wed Mar 7 01:03:39 2007 - - 3 Answers - 0 Comments
A. Sectioning is important. If you don't section the hair off in small areas when cutting, you won't get an even line. When I was in my first cosmetology school, I was taught to section the hair in six areas - from ear to ear across the top of the head, then down the middle from the forehead to the nape of the neck, then splitting the back portion in half around the occipital bone. Right? When I transferred to a much better school I learned that it was better to do small sections. Section the front into three (not two) sections - one section on top of the head from forehead to crown, about the width where the skull begins to curve down towards the ear. Then comb a section from the tip of the ear towards the front. Then section the back… [cont.]
Answered by wickdsinnr - Wed Mar 7 01:30:09 2007
How do you get rid of a tension headache?
Q. I have this horrible tension headache but there are few meds I can take. I had a reaction to Excedrin tension headache and there are many cold medicines that don't react well. Unfortunately, I don't know until my ears swell up and turn numb while my body itches with hives and I have to go the er once again.
Asked by Kayla - Wed Oct 15 15:39:20 2008 - - 1 Answers - 0 Comments
A. Try Head-On. I bought it as a fluke & was amazed at how well it works. You can also try Active-On. Rub it on the back of your neck & your shoulder blades. Amazing! Don't dwell on the tension. Worrying and/or getting upset about the fact that tension affects you only makes it worse. When you notice it smear on the Head/Active-On, shut your eyes & go away for a few minutes. Imagine you're on a beach or walking your dog or buying a new purse -- whatever makes you happy.
Answered by mean cats mama - Wed Oct 15 16:37:58 2008
Q. I have this horrible tension headache but there are few meds I can take. I had a reaction to Excedrin tension headache and there are many cold medicines that don't react well. Unfortunately, I don't know until my ears swell up and turn numb while my body itches with hives and I have to go the er once again.
Asked by Kayla - Wed Oct 15 15:39:20 2008 - - 1 Answers - 0 Comments
A. Try Head-On. I bought it as a fluke & was amazed at how well it works. You can also try Active-On. Rub it on the back of your neck & your shoulder blades. Amazing! Don't dwell on the tension. Worrying and/or getting upset about the fact that tension affects you only makes it worse. When you notice it smear on the Head/Active-On, shut your eyes & go away for a few minutes. Imagine you're on a beach or walking your dog or buying a new purse -- whatever makes you happy.
Answered by mean cats mama - Wed Oct 15 16:37:58 2008
What is the best tension for a badminton racket?
Q. I am an intermediate player with a yonex muscle power 99 and i was just wondering what would be the best tension. I primarily play doubles but i also play singles. Thanks!
Asked by frank - Fri Sep 18 21:34:07 2009 - - 2 Answers - 0 Comments
A. String tension is usually up to personal preference. It's not that clear how lower/higher tensions affect play since not much study has gone into that area. I find that the higher tension you use, the better your technique needs to be. Basically, the better you are, the higher tension you go.
Answered by Badminton Player - Sat Sep 19 20:36:29 2009
Q. I am an intermediate player with a yonex muscle power 99 and i was just wondering what would be the best tension. I primarily play doubles but i also play singles. Thanks!
Asked by frank - Fri Sep 18 21:34:07 2009 - - 2 Answers - 0 Comments
A. String tension is usually up to personal preference. It's not that clear how lower/higher tensions affect play since not much study has gone into that area. I find that the higher tension you use, the better your technique needs to be. Basically, the better you are, the higher tension you go.
Answered by Badminton Player - Sat Sep 19 20:36:29 2009
How to find the tension of a string connecting two masses?
Q. Two masses M1 = 5.50 kg and M2 = 4.30 kg are on a frictionless surface, attached by a thin string. A force of 104.5 N pulls on M2 at an angle of 31.5 from the horizontal. Find the tension T in the string connecting the two blocks.
Asked by Gogreen - Wed Jul 15 19:25:47 2009 - - 2 Answers - 0 Comments
A. First step is to find the acceleration of the entire system. The net force acting on the system is 104.5 N at an angle of 31.5. We are concerned with the horizontal component of this force because it is being pulled across a table and the horizontal component is 104.5N cos 31.5 = 89.1N. Alright, so the net horizontal force is 89.1N and this is accelerating the system with a total mass of 5.5kg + 4.3kg = 9.8kg. Using the equation F = MA we can find the acceleration of the entire system to be 89.1N / 9.8 kg = 9.092 m/s/s. So block M1 is 5.5 kg being accelerated at 9.092 m/s/s and this is going to require a force of (F = MA) F = 5.5 kg * 9.092 m/s/s = 50.00 N. The only object that can apply this force to block M1 is the string and so… [cont.]
Answered by HuntGather - Wed Jul 15 20:14:42 2009
Q. Two masses M1 = 5.50 kg and M2 = 4.30 kg are on a frictionless surface, attached by a thin string. A force of 104.5 N pulls on M2 at an angle of 31.5 from the horizontal. Find the tension T in the string connecting the two blocks.
Asked by Gogreen - Wed Jul 15 19:25:47 2009 - - 2 Answers - 0 Comments
A. First step is to find the acceleration of the entire system. The net force acting on the system is 104.5 N at an angle of 31.5. We are concerned with the horizontal component of this force because it is being pulled across a table and the horizontal component is 104.5N cos 31.5 = 89.1N. Alright, so the net horizontal force is 89.1N and this is accelerating the system with a total mass of 5.5kg + 4.3kg = 9.8kg. Using the equation F = MA we can find the acceleration of the entire system to be 89.1N / 9.8 kg = 9.092 m/s/s. So block M1 is 5.5 kg being accelerated at 9.092 m/s/s and this is going to require a force of (F = MA) F = 5.5 kg * 9.092 m/s/s = 50.00 N. The only object that can apply this force to block M1 is the string and so… [cont.]
Answered by HuntGather - Wed Jul 15 20:14:42 2009
What are the building restrictions under high tension power lines?
Q. I'm looking at a parcel of raw land for sale that has a high tension power line that goes over part of the property. I want to know what the setback restrictions are for building or using the space under or near high tension lines to determine the development value for the land. If the setback is 100 feet, then it would greatly limit the uses of this parcel of land. It's only 4 acres and the power line goes over one corner of the property. Thanks.
Asked by jgradyc - Thu Nov 26 17:27:11 2009 - - 2 Answers - 0 Comments
A. You cannot build under any power line. Determine the distance you can build by the amount of land kept cleared under the lines. You cannot build in this zone. If you lose 1/4 of the land to use, you will have about 130,000 square feet remaining.
Answered by Rondi - Thu Nov 26 21:20:46 2009
Q. I'm looking at a parcel of raw land for sale that has a high tension power line that goes over part of the property. I want to know what the setback restrictions are for building or using the space under or near high tension lines to determine the development value for the land. If the setback is 100 feet, then it would greatly limit the uses of this parcel of land. It's only 4 acres and the power line goes over one corner of the property. Thanks.
Asked by jgradyc - Thu Nov 26 17:27:11 2009 - - 2 Answers - 0 Comments
A. You cannot build under any power line. Determine the distance you can build by the amount of land kept cleared under the lines. You cannot build in this zone. If you lose 1/4 of the land to use, you will have about 130,000 square feet remaining.
Answered by Rondi - Thu Nov 26 21:20:46 2009
How do you find the tension in a string on a bow and arrow?
Q. Pulling the string on a bow back with a force of 27.0 , an archer prepares to shoot an arrow. If the archer pulls in the center of the string, and the angle between the two halves is 138 , what is the tension in the string? It's a force of 27.0 lbs and the angle is in degrees.
Asked by Jaime - Sun Oct 11 20:25:09 2009 - - 1 Answers - 0 Comments
A. You'll find this problem much easier if you draw it, I'm somewhat limited by the medium of text, so this will probably not help you all that much: cos(138/2) = 27 / F F = 27 / cos(69) F = 75.3 pounds-force to three significant figures. Consider the 27.0 pounds-force to be one side of a right angled triangle, the tension in the string is the hypoteneuse of the triangle. The 69 degrees is the angle between these two sides, or forces.
Answered by lavalamp3773 - Sun Oct 11 20:35:28 2009
Q. Pulling the string on a bow back with a force of 27.0 , an archer prepares to shoot an arrow. If the archer pulls in the center of the string, and the angle between the two halves is 138 , what is the tension in the string? It's a force of 27.0 lbs and the angle is in degrees.
Asked by Jaime - Sun Oct 11 20:25:09 2009 - - 1 Answers - 0 Comments
A. You'll find this problem much easier if you draw it, I'm somewhat limited by the medium of text, so this will probably not help you all that much: cos(138/2) = 27 / F F = 27 / cos(69) F = 75.3 pounds-force to three significant figures. Consider the 27.0 pounds-force to be one side of a right angled triangle, the tension in the string is the hypoteneuse of the triangle. The 69 degrees is the angle between these two sides, or forces.
Answered by lavalamp3773 - Sun Oct 11 20:35:28 2009
How do i work out tension for mechanics question?
Q. A particle P is attached to one end of a light inextensible string. The other end of the string is attached to a fixed point O. A horizontal force of magnitude 12N is applied to P. The particle P is in equilibrium with the string taut and OP making an angle of 20degrees with the downward vertical. Find (a) the tension in the string. (b) the weight of P.
Asked by Alex - Wed Mar 10 16:28:28 2010 - - 1 Answers - 0 Comments
A. Let us assume that the tension in the string is equal to T. For the point P to be in equillibrium, the T.Sine of 20 degrees must be equal to 12N. Hence, T = 12/Sin(20) or T= 35.086N P is equal to T Cos(20) or 32.970 N
Answered by kalroc - Wed Mar 10 16:38:42 2010
Q. A particle P is attached to one end of a light inextensible string. The other end of the string is attached to a fixed point O. A horizontal force of magnitude 12N is applied to P. The particle P is in equilibrium with the string taut and OP making an angle of 20degrees with the downward vertical. Find (a) the tension in the string. (b) the weight of P.
Asked by Alex - Wed Mar 10 16:28:28 2010 - - 1 Answers - 0 Comments
A. Let us assume that the tension in the string is equal to T. For the point P to be in equillibrium, the T.Sine of 20 degrees must be equal to 12N. Hence, T = 12/Sin(20) or T= 35.086N P is equal to T Cos(20) or 32.970 N
Answered by kalroc - Wed Mar 10 16:38:42 2010
How would I mesure the tension on a bow and arrow?
Q. I need to be able to measure the tension at different intervals on a simple bow.
Asked by Kelsey - Wed Aug 5 15:56:58 2009 - - 1 Answers - 0 Comments
A. Tension on bow would be force exerted by arrow equals the force exerted by your pull on the arrow. According to Newton's third law, the same tension will be the on arrow which makes it to travel distance!!!
Answered by Manu - Wed Aug 5 16:06:19 2009
Q. I need to be able to measure the tension at different intervals on a simple bow.
Asked by Kelsey - Wed Aug 5 15:56:58 2009 - - 1 Answers - 0 Comments
A. Tension on bow would be force exerted by arrow equals the force exerted by your pull on the arrow. According to Newton's third law, the same tension will be the on arrow which makes it to travel distance!!!
Answered by Manu - Wed Aug 5 16:06:19 2009
What is the magnitude of the tension on the ends of the clothesline?
Q. A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 4 kilograms is tied to the middle of the clothesline, it sags a distance of 4 meters. What is the magnitude of the tension on the ends of the clothesline?
Asked by Mitchel Cabrera - Wed Feb 17 17:16:52 2010 - - 1 Answers - 0 Comments
A. Don't you mean what's the tension of the magnitude at the clothes line ends?
Answered by Common Sense Pro - Wed Feb 17 17:17:58 2010
Q. A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 4 kilograms is tied to the middle of the clothesline, it sags a distance of 4 meters. What is the magnitude of the tension on the ends of the clothesline?
Asked by Mitchel Cabrera - Wed Feb 17 17:16:52 2010 - - 1 Answers - 0 Comments
A. Don't you mean what's the tension of the magnitude at the clothes line ends?
Answered by Common Sense Pro - Wed Feb 17 17:17:58 2010
How do I pull back the tension wheel when installing a timing belt?
Q. It's a 2002 Pt Cruiser. The process of replacing the timing belt isn't hard, but there's a tension wheel you pull back to slip the belt into place and we're having a hard time getting the wheel to go all the way back. Is there a tool we need or maybe just a certain approach? Basically, I wonder what the dealership can do that we can't. They must have a method for doing this. Thank You. Note: The tension wheel is a spring loaded wheel intended to make the belt installation a little easier by not having to remove the wheel itself. In theory it sounds easy that it should be able to be pushed back but that's the tricky part. We have a manual for this, as we do with all our vehicles. The manual honestly does not tell you how to pull… [cont.]
Asked by testmeet - Sun May 21 18:24:39 2006 - - 2 Answers - 0 Comments
A. i could be wrong, but i think there are 2 adjusters on the tensioner pulley. one is on a spring loaded cam, and the other is on a pivot and a elongated slide hole in the bearing. get a manual if you insist on doing it yourself. if you get something wrong, you could cause major engine damage, so get a step by step manual on this repair, and follow it carefully. a little extra time and money will save a huge headache later.
Answered by whattf - Sun May 21 19:41:51 2006
Q. It's a 2002 Pt Cruiser. The process of replacing the timing belt isn't hard, but there's a tension wheel you pull back to slip the belt into place and we're having a hard time getting the wheel to go all the way back. Is there a tool we need or maybe just a certain approach? Basically, I wonder what the dealership can do that we can't. They must have a method for doing this. Thank You. Note: The tension wheel is a spring loaded wheel intended to make the belt installation a little easier by not having to remove the wheel itself. In theory it sounds easy that it should be able to be pushed back but that's the tricky part. We have a manual for this, as we do with all our vehicles. The manual honestly does not tell you how to pull… [cont.]
Asked by testmeet - Sun May 21 18:24:39 2006 - - 2 Answers - 0 Comments
A. i could be wrong, but i think there are 2 adjusters on the tensioner pulley. one is on a spring loaded cam, and the other is on a pivot and a elongated slide hole in the bearing. get a manual if you insist on doing it yourself. if you get something wrong, you could cause major engine damage, so get a step by step manual on this repair, and follow it carefully. a little extra time and money will save a huge headache later.
Answered by whattf - Sun May 21 19:41:51 2006
How do you adjust the cam tension for a fzx700s?
Q. I have a Rare, 86' Fazer 700s and the cam chain is rattling i need to adjust the tension on it but i don't have a service manual. Is there anyone that can tell me were the adjust point is on the external of the engine?
Asked by Sidewinder - Mon Jun 16 14:01:13 2008 - - 1 Answers - 0 Comments
A. my answer is try to check it out first on auto repair shop..
Answered by alex p - Fri Jun 20 07:06:59 2008
Q. I have a Rare, 86' Fazer 700s and the cam chain is rattling i need to adjust the tension on it but i don't have a service manual. Is there anyone that can tell me were the adjust point is on the external of the engine?
Asked by Sidewinder - Mon Jun 16 14:01:13 2008 - - 1 Answers - 0 Comments
A. my answer is try to check it out first on auto repair shop..
Answered by alex p - Fri Jun 20 07:06:59 2008
What's the difference between tension headaches and migraines?
Q. My husband has severe headaches. The Dr said it was tension headaches and a sinus infection. What I read on the internet suggests that these symptoms could also be migraines. Migraines run in his family and are currently being treated poorly. Suggestions?
Asked by annie_lubbers - Thu Jun 22 00:00:17 2006 - - 2 Answers - 0 Comments
A. headache is a pain in the head. Approximately seven of 10 people get headaches. A headache may be located in any part of the head and may even extend to the neck. The problem can be acute (short and isolated) or chronic (a common occurrence). Most headaches are painful and annoying but can be easily relieved with aspirin or acetaminophen. However, in some cases head pain becomes severe and debilitating, and occasionally a headache is a symptom of a serious underlying medical problem A migraine is a common form of primary headache. Migraine pain seems to run in families, and women are three times more likely than men to experience this type of headache. The onset is usually between age 10 and 46 years. Seventy to 80 percent of all migraine… [cont.]
Answered by shortygoldstein - Thu Jun 22 00:05:14 2006
Q. My husband has severe headaches. The Dr said it was tension headaches and a sinus infection. What I read on the internet suggests that these symptoms could also be migraines. Migraines run in his family and are currently being treated poorly. Suggestions?
Asked by annie_lubbers - Thu Jun 22 00:00:17 2006 - - 2 Answers - 0 Comments
A. headache is a pain in the head. Approximately seven of 10 people get headaches. A headache may be located in any part of the head and may even extend to the neck. The problem can be acute (short and isolated) or chronic (a common occurrence). Most headaches are painful and annoying but can be easily relieved with aspirin or acetaminophen. However, in some cases head pain becomes severe and debilitating, and occasionally a headache is a symptom of a serious underlying medical problem A migraine is a common form of primary headache. Migraine pain seems to run in families, and women are three times more likely than men to experience this type of headache. The onset is usually between age 10 and 46 years. Seventy to 80 percent of all migraine… [cont.]
Answered by shortygoldstein - Thu Jun 22 00:05:14 2006
Is it necessary to install a tension or extension spring on a manual roll-up garage/shed door?
Q. Would like to install a roll-up door on my shed, and I'm thinking of using an ordinary garage door to do this. Are tension springs necessary, since I will be opening the door manually?
Asked by Curious Gardener - Mon Mar 17 18:13:54 2008 - - 2 Answers - 0 Comments
A. No, but the door wont stay open and it gets pretty heavy. Hard to hold it hope while putting things in or taking things out.
Answered by Fresh - Mon Mar 17 18:17:29 2008
Q. Would like to install a roll-up door on my shed, and I'm thinking of using an ordinary garage door to do this. Are tension springs necessary, since I will be opening the door manually?
Asked by Curious Gardener - Mon Mar 17 18:13:54 2008 - - 2 Answers - 0 Comments
A. No, but the door wont stay open and it gets pretty heavy. Hard to hold it hope while putting things in or taking things out.
Answered by Fresh - Mon Mar 17 18:17:29 2008
How to calculate tension in a cord when the cord has mass?
Q. I know how to deal with tension in a massless cord, but what if the cord has mass? Here is the specific question: A block of mass M is attached to a cord of mass m and length , which is fixed at one end. The block moves in a horizontal circle on a frictionless table. If the period of the circular motion is P, find the tension in the cord as a function of radial position along the cord, 0 <= r <= L. Apparently an integral needs to be set up, but I don't know how to approach it. Sorry, the cord has a length of L.
Asked by Jacqueline Sherry - Mon Feb 19 17:40:26 2007 - - 1 Answers - 0 Comments
A. You can do the following. 1. Angular velocity w is constant = 2pi/P 2. At the tip of the cord, the tension is equal to the centripetal force pulling on M, T(M)= MLw^2, this will stay constant 3. For the rope, let p= linear mass density = m/L Consider a small mass dm at distance x from the opposite end of the cord, then integrate the force F (r) = Integrate from r to L{ (L-x)w^2 dm} + T(M) = Int from r toL { mw^2/L * (L-x)dx + TM = mw^2/L * { L(L-r) - 1/2 * (L^2- r^2)} + T(M) = mw^2/L * 1/2 * (L-r)^2 + T(M) Test answer a. r=L, F(r=L) = T(M) b. r=0, F(r=0) = T(M) +1/2* mLw^2 The 1/2L is the center of mass of the cord so it is as if the cord of mass is located at 1/2L, together with the M at L.
Answered by Sir Richard - Mon Feb 19 18:44:57 2007
Q. I know how to deal with tension in a massless cord, but what if the cord has mass? Here is the specific question: A block of mass M is attached to a cord of mass m and length , which is fixed at one end. The block moves in a horizontal circle on a frictionless table. If the period of the circular motion is P, find the tension in the cord as a function of radial position along the cord, 0 <= r <= L. Apparently an integral needs to be set up, but I don't know how to approach it. Sorry, the cord has a length of L.
Asked by Jacqueline Sherry - Mon Feb 19 17:40:26 2007 - - 1 Answers - 0 Comments
A. You can do the following. 1. Angular velocity w is constant = 2pi/P 2. At the tip of the cord, the tension is equal to the centripetal force pulling on M, T(M)= MLw^2, this will stay constant 3. For the rope, let p= linear mass density = m/L Consider a small mass dm at distance x from the opposite end of the cord, then integrate the force F (r) = Integrate from r to L{ (L-x)w^2 dm} + T(M) = Int from r toL { mw^2/L * (L-x)dx + TM = mw^2/L * { L(L-r) - 1/2 * (L^2- r^2)} + T(M) = mw^2/L * 1/2 * (L-r)^2 + T(M) Test answer a. r=L, F(r=L) = T(M) b. r=0, F(r=0) = T(M) +1/2* mLw^2 The 1/2L is the center of mass of the cord so it is as if the cord of mass is located at 1/2L, together with the M at L.
Answered by Sir Richard - Mon Feb 19 18:44:57 2007
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